LOL, they're just trying to mess with your head.
Both relays are tied to the B+ (12 v) and the circuit board pulls the other side of the relay coil to ground and energizes the relay.
So remember we're looking for a potential difference to energize the relays. Place the positive lead of the multimeter on the always hot side, feeding the relay and the negative lead on the circuit board side of the relay.
When the circuit board pulls that terminal to ground, you will then have a potential difference
across the relay coil and it will be energized. And you will read 12 volts
across the relay coil as apposed to reading on both sides wrt chassis ground.
If the circuit board doesn't pull the terminal to ground, you will not see a 12 V potential
across the coil.
It's all about where you're referencing ground. If you use chassis ground as the reference, you will see 12 V on both sides of the relay coil because the coil passes DC from the always hot side.
At least until the circuit board pulls one side to ground. Then, only the always hot side of the coil will have 12 wrt to chassis ground.
Does that make sense?
In one of my previous posts, I identified that the PCM applied a ground signal to one side of the coil. That was the important part of that post.
Let me know if that's clear or not.
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